1.2x^2=40

Solution for 1.2x^2=40 equation:

1.2x^2=40

We move all terms to the left:

1.2x^2-(40)=0

a = 1.2; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·1.2·(-40)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*1.2}=\frac{0-8\sqrt{3}}{2.4}
=-\frac{8\sqrt{3}}{2.4}
=-\frac{4\sqrt{3}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*1.2}=\frac{0+8\sqrt{3}}{2.4}
=\frac{8\sqrt{3}}{2.4}
=\frac{4\sqrt{3}}{1.2}
$